Question

resolve into factors:
${x}^{2} {y}^{2} {z}^{4} + {y}^{2} {z}^{2} {p}^{2} + 2 {xy}^{2} {z}^{3} p$

Answer 1

$\textbf{Solution :}$

“Here, you can use this formula —”

Formula,

(a + b)² = a² + b² + 2ab

“according to the formula —”

♦ x²y²z⁴ + y²z²p² + 2xy²z³p

= (xyz²)² + (yzp)² + 2(xyz²) (yzp)

= (xyz² + yzp)²

$\textbf{Answer :}$ (xyz² + yzp)²

$\textbf{Step 1}$

“If we look at it deeply,”

x²y²z⁴ + y²z²p² + 2xy²z³p

= x×x×y×y×z×z×z×z + y×y×z×z×p×p + 2×x×y×y×z×z×z×p

“So, it can also be written as,”

= (xyz²)² + (yzp)² + 2(xyz²) (yzp)

because, it is same as,

= (xyz²)² + (yzp)² + 2(xy²z³p)

$\textbf{Last Step}$

“according to the formula,”

a² + b² + 2ab

= (xyz²)² + (yzp)² + 2(xyz²) (yzp)

Is equals to —

(a + b)²

= (xyz² + yzp)²
___________________
$\boxed{Hope\:it\:helps\:you!}$

$\boxed{Have\:a\:great\:day\:ahead!}$
____________________

#be brainly

Answer 2

Hello dear your answer is in photo

Hope it helps you
If you need any help say me okBye