resolve into factors; x^3 y - 64y^4
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3
Answer:
x^3y-64y^4
y(x^3-64y^3)
y{x^3-(4y)^3}
y(x-4y)(x^2+4xy+16y^2)
Answered by
0
Answer:
Rewriting 64y^4 is 4y^3
X^3 - 4y^3
We use formula a^3 - b^3
= (a - b) (a^2 + ab + b^2)
(x - (4y)) (x^2 + x (4y) + (4y)^2)
= ( x - 4y) ( x^2 + 4xy + 16 y^2) answer
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