Question

resolve into factors x2-√3x-6​

Answer 1

Answer:

${x}^{2} - \sqrt{3} x - 6 = 0$

$x(x - \sqrt{3} ) - 6 = 0$

$(x - \sqrt{3)} (x - 6) = 0$

$x = \sqrt{3} \: and6$

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Answer 2

Answer:

$(x + \sqrt{3} )(x - 2 \sqrt{3} )$

Step-by-step explanation:

$x {}^{2} - \sqrt{3} x - 6 \\ = x {}^{2} - 2 \sqrt{3} x + \sqrt{3} x - 6 \\ = x(x - 2 \sqrt{3} ) + \sqrt{3} (x - 2 \sqrt{3} ) \\ = (x + \sqrt{3} )(x - 2 \sqrt{3} )$