Resolve into factors x³+3x²+3x-7
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Answer:
(x-1)(x²+4x+7)
Explanation:
Let p(x) = x³+3x²+3x-7
Sum of the coefficients
= 1+3+3-7
= 0
Therefore,
(x-1) is a factor of p(x).
x-1)x³+3x²+3x-7(x²+4x+7
****x³-x²
________________
*******4x²+3x-7
*******4x²-4x
________________
***********7x-7
***********7x-7
________________
Remainder (0)
Therefore,
p(x) = (x-1)(x²+4x+7)
••••
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