Question

resolve into partial fraction 11-3x÷(x-1)(x+3)​

Answer 1

Answer:

$\dfrac{2}{x-1} - \dfrac{5}{x+3}$

Step-by-step explanation:

$\dfrac{11-3x}{(x-1)(x+3)} = \dfrac{A}{x-1} + \dfrac{B}{x+3}\\\dfrac{11-3x}{(x-1)(x+3)} = \dfrac{A(x+3) + B(x-1)}{(x-1)(x+3)}\\\\11-3x = (A+B)x + 3A -B\\A + B = -3\\3A-B = 11$

On solving this system of linear equations,

$A = 2, B = -5$