Math, asked by vaishnavpatil1143, 9 months ago

resolve into partial fraction​

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Answered by ravikishore01
3

Answer:

 \frac{a}{  {x}^{2}  + 1}  +  \frac{b}{ {x}^{2}  + 2}  =  \frac{ {x}^{2} }{( {x}^{2}  + 1)( {x}^{2}  + 2)}    \\   \frac{a( {x}^{2} + 2) \:  + b( {x}^{2}  + 1) }{( {x}^{2} + 1)( {x}^{2} + 2)  }  =  \frac{ {x}^{2} }{( {x}^{2} + 1)( {x}^{2}   + 2}  \\  ( a {x}^{2}  + b {x}^{2} ) + (2a + b)  =  {x}^{2}   \\ a + b = 1 \\ 2a + b = 0 \\ a =  - 1 \:  \:  \:  \:  \: b =  - 2 \\  \frac{ - 1}{ {x}^{2}  + 1}  +  \frac{ - 2}{ {x}^{2}  + 2}

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