Question

resolve into partial fraction 3х - 1/
(x-1)(х-2)(х-3​

Answer 1

The answer is =−93x+2+72x+1

Explanation:

Perform the decomposition into partial fractions

3x+5(3x+2)(2x+1)=A3x+2+B2x+1

=A(2x+1)+B(3x+2)(3x+2)(2x+1)

Compare the numerators

3x+5=A(2x+1)+B(3x+2)

Let x=−23

Then,

3=−13A

⇒, A=−9

Let x=−12

Then,

72=12B

⇒, B=7

Finally,

3x+5(3x+2)(2x+1)