Question

resolve into partial fraction 3x+1/(x_2)(X+1)
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Answer 1

This is ur answer hope this will help u

Answer 2

Answer:

7/3(x-2) + 2/3(X+1)

Step-by-step explanation:

3x+1/(x-2)(X+1)=A/X-2 + B/X+1

LCM

3x+1/(x-2)(X+1)=A(X+1)+B(x-2)/(x-2)(X+1)

both the denominator are same so let's cancel them

3x+1=A(X+1)+B(x-2)----------1

when X=2, after simplyfying we get A=7/3

when X=1 , after substituting A's value we get B=2/3

substituting A and B value in eq 1

3x+1/(x-2)(X+1)=7(X+1)/3(x-2)(X+1)+2(x-2)/3(x-2)(X+1)