Question

resolve into partial fraction
3x^2+5/(x-1)(X+1)^2​

Answer 1

Answer:

      (x−1)(x+2)29=x−1A+x+2B+(x+2)2C

               =>9=A(x+2)2+B(x−1)(x+2)+C(x−1)               -(1)

   For x=1,=>9=A(3)2+B(0)+C(0)

                 =>9=9A

                 =>A=1          - (2)

For  x=−2,=>9=A(0)+B(0)+C(−2−1)

                 =>9=−3C

                 =>C=−3              -(3)

Now , we have found out value of A and C , to find value of B , put x = any real number .

     Let x =0 , then equation (1) reduces to 9=4A−2B−C

                =>9=4−2B

                =>2=−2B

                 =>B=−1          -(4)

Therefore from (2),(3),(4) we get (x−1)(x+2)29=x−11−

Answer 2

Answer:

This is the right answer according to me.