Resolve into partial fraction 3x+2
(x + 1) (x×x-1)
Answers
Answered by
1
Answer:
don't know
Step-by-step explanation:
don't know sorry sorry
Answered by
1
Step-by-step explanation:
So ,
(1−2x)(1−x
2
)
1+3x+2x
2
=
(1−2x)(1−x)(1+x)
1+3x+2x
2
=>
(1−2x)(1−x)(1+x)
1+3x+2x
2
=
1−2x
A
+
1−x
B
+
1+x
C
=>1+3x+2x
2
=A(1−x)(1+x)+B(1−2x)(1+x)+C(1−2x)(1−x)
For x=1,=>1+3(1)+2(1)
2
=A(0)+B(1−2)(1+1)+C(0)
=>6=−2B
=>B=−3 −(1)
For x=−1,=>1+3(−1)+2(−1)
2
=A(0)+B(0)+C(1−2(−1))(1−(−1))
=>0=6C
=>C=0 −(2)
For x=
2
1
,=>1+3(
2
1
)+2(
2
1
)
2
=A(
2
1
)(1+
2
1
)+B(0)+C(0)
=>3=
4
3
A
=>A=4 −(3)
Therefore , from (1),(2) and (3) =>
(1−2x)(1−x)(1+x)
1+3x+2x
2
=
1−2x
4
−
1−x
3
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