Question

Resolve into partial fraction x/(x²+1) (x²+4)?
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Answer 1

Answer:

Letx2+1(x−1)2(x2+2x+2)=Ax−1+B(x−1)2+Cx+Dx2+2x+2

⟹x2+1=A(x−1)(x2+2x+2)+B(x2+2x+2)

+Cx(x−1)2+D(x−1)2(1)

⟹x2+1=A(x3+x2−2)+B(x2+2x+2)

+C(x3−2x2+x)+D(x2−2x+1)

when x = 1

1+1=B(1+2+2)⟹B=25