Question

: Resolve into partial fractions
1. 3x+7
x²-3x+2​

Answer 1

Answer:

$\frac{13}{x-2}-\frac{10}{x-1}$

Step-by-step explanation:

I think you want me to resolve this,

$\frac{3x+7}{x^2-3x+2}$.

Resolve x²-3x+2 into factors.

x²-3x+2 = x² -2x -x +2

             = x(x-2) -(x-2)

             = (x-1)(x-2)

Now the fraction becomes

$\frac{3x+7}{(x-1)(x-2)} = \frac{A}{x-1} +\frac{B}{x-2}$  Here A,B represent any two Real numbers.

3x+7 = A(x-2) + B(x-1)

3x+7 = (A+B)x -2A - B

Comparing coefficient of x and constant,

A+B = 3 and 2A +B = -7

Solve these equations,

B = 3 - A. substitute this is another equation.

2A + 3 -A = -7

A = -10

And B = 13

Therefore,

$\frac{3x+7}{x^2-3x+2} = \frac{13}{x-2}-\frac{10}{x-1}$.

Answer 2

Answer:

can't we get the answer A as -10 and B as 13 please reply fast