Question

Resolve into partial fractions 4x+1÷(x-2)(x+1)

Answer 1

Step-by-step explanation:

Let

$\frac{4x + 1}{(x - 2)(x + 1)} = \frac{a}{(x - 2)} + \frac{b}{(x + 1)}$

$= > \frac{4x + 1}{(x - 2)(x + 1)} = \frac{a(x + 1) + b(x - 2)}{(x - 2)(x + 1)}$

$= > 4x + 1 = (a + b)x + (a - 2b)$

On comparing, we get,

$a + b = 4 \: \: and \: \: a - 2b = 1$

On solving these equation,

we get,

$a = 3 \: \: and \: \: b = 1$