Question

Resolve into partial fractions:
sin theta+1
(sin theta+2)(sin theta +3)​

Answer 1

Step-by-step explanation:

OK, let's try the tangent half-angle substitution:

tanθ2θsinθcosθ=t=2arctant=sin(2arctant)=2sin(arctant)cos(arctant)=2tt2+1−−−−−√⋅1t2+1−−−−−√=2tt2+1=cos(2arctant)=cos2arctant−sin2arctant=(1t2+1