Question

resolve into partial fractions x+4÷x^2×x+1​

Answer 1

Answer :

= ${\sf{x + 4 ÷ {x}^{2} × x + 1}}$

= ${\sf{x +\dfrac{ 4 }{ {x}^{2} } × x + 1}}$

= ${\sf{x +\dfrac{ 4 }{ \cancel{{x}^{2} }} × \cancel{x} + 1}}$

= ${\sf{x +\dfrac{ 4 }{ x } + 1}}$

= ${\sf{\dfrac{{x}^{2} + 4 + x}{ x } }}$

= ${\sf{\dfrac{{x}^{2} + x + 4}{ x } }}$

Thank you!! :D

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