Question

Resolve the 1/(x+11)(x-3) into partial fraction

Answer 1

Answer:

The answer is $\dfrac{\frac{1}{14}}{x-3}-\dfrac{\frac{1}{14}}{x+11}$

Step-by-step explanation:

Given expression is

   $\dfrac{1}{(x+11)(x-3)}=\dfrac{1}{14}\dfrac{(x+11)-(x-3)}{(x+11)(x-3)}$

                            $=\dfrac{1}{14}(\dfrac{(x+11)}{(x+11)(x-3)}-\dfrac{(x-3)}{(x+11)(x-3)})\\\\=\dfrac{1}{14}(\dfrac{1}{(x-3)}-\dfrac{1}{x+11})\\\\=\dfrac{\frac{1}{14}}{x-3}-\dfrac{\frac{1}{14}}{x+11}$