Question

resolve the factors
a²-6a+9

Answer 1

Answer:

We will break 9 as 3 square

Then,

Our answer is (a-3)whole of square

Answer 2

Answer:

$a^{2} + 6a + 9\\a^{2} + 3a+3a + 9\\a(a+3) + 3(a+3)\\(a+3) (a+3)\\(a+3)^{2}$

Hope this helps you..

Mak mine as Brainliest please