Math, asked by guruji7818, 3 months ago

resolve the following into factors 4x2- 4/3x + 1/9​

Answers

Answered by keybytegamer1m
1

Answer:

How to solve your problem

4

2

1

4

3

+

1

9

4x^{2}-1 \cdot \frac{4}{3} \cdot x+\frac{1}{9}

4x2−1⋅34⋅x+91

Simplify

1

Multiply the numbers

4

2

1

4

3

+

1

9

4x^{2}{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{4}{3}}}x+\frac{1}{9}

4x2−1⋅34x+91

4

2

4

3

+

1

9

4x^{2}{\color{#c92786}{-\frac{4}{3}}}x+\frac{1}{9}

4x2−34x+91

2

Combine multiplied terms into a single fraction

4

2

4

3

+

1

9

4x^{2}-\frac{4}{3}x+\frac{1}{9}

4x2−34x+91

4

2

+

4

3

+

1

9

4x^{2}+\frac{-4x}{3}+\frac{1}{9}

4x2+3−4x+91

3

Find common denominator

4

2

+

4

3

+

1

9

4x^{2}+\frac{-4x}{3}+\frac{1}{9}

4x2+3−4x+91

3

4

2

3

+

4

3

+

3

1

9

3

\frac{3 \cdot 4x^{2}}{3}+\frac{-4x}{3}+\frac{3 \cdot \frac{1}{9}}{3}

33⋅4x2+3−4x+33⋅91

4

Combine fractions with common denominator

3

4

2

3

+

4

3

+

3

1

9

3

\frac{3 \cdot 4x^{2}}{3}+\frac{-4x}{3}+\frac{3 \cdot \frac{1}{9}}{3}

33⋅4x2+3−4x+33⋅91

3

4

2

4

+

3

1

9

3

\frac{3 \cdot 4x^{2}-4x+3 \cdot \frac{1}{9}}{3}

33⋅4x2−4x+3⋅91

5

Multiply the numbers

3

4

2

4

+

3

1

9

3

\frac{{\color{#c92786}{3}} \cdot {\color{#c92786}{4}}x^{2}-4x+3 \cdot \frac{1}{9}}{3}

33⋅4x2−4x+3⋅91

1

2

2

4

+

3

1

9

3

\frac{{\color{#c92786}{12}}x^{2}-4x+3 \cdot \frac{1}{9}}{3}

312x2−4x+3⋅91

6

Multiply the numbers

1

2

2

4

+

3

1

9

3

\frac{12x^{2}-4x+{\color{#c92786}{3}} \cdot {\color{#c92786}{\frac{1}{9}}}}{3}

312x2−4x+3⋅91

1

2

2

4

+

1

3

3

\frac{12x^{2}-4x+{\color{#c92786}{\frac{1}{3}}}}{3}

312x2−4x+31

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