Question

Resolve the following into factors :
9x^2+42xy+49y^2​

Answer 1

Answer:

Thus, in factored form 9x^2+42xy+49y^29x

2

+42xy+49y

2

is written as (3x+7y)(3x+7y)(3x+7y)(3x+7y)

Step-by-step explanation:

Consider the given equation, 9x^2+42xy+49y^29x

2

+42xy+49y

2

We need to factorize the given equation,

Factorization is a method of writing an expression in factor terms such that when we take the product we get back the original expression.

Using identity (a+b)^2=a^2+2ab+b^2(a+b)

2

=a

2

+2ab+b

2

for the given expression ,

Given expression can be written as ,

9x^2+42xy+49y^2=(3x)^2+2 \cdot 3x\cdot 7y+(7y)^29x

2

+42xy+49y

2

=(3x)

2

+2⋅3x⋅7y+(7y)

2

On comparing, we get a = 3x and b = 7y

Thus, 9x^2+42xy+49y^2=(3x+7y)^29x

2

+42xy+49y

2

=(3x+7y)

2

Thus, in factored form 9x^2+42xy+49y^29x

2

+42xy+49y

2

is written as (3x+7y)(3x+7y)(3x+7y)(3x+7y)

Step-by-step explanation:

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