Math, asked by nikhilkokane36, 1 day ago

Resolve the following into partial fractions : 1/(x-1)²(x+4)​

Answers

Answered by navaneethkrishna94
0

Answer:

1/x³+2x²-7x+4

Step-by-step explanation:

1/x²+1-2x(x+4)

1/x³+4x²+x+4-2x²-8x

1/x³+2x²-7x+4

Answered by pp209325
2

Answer:

======x2+1(x−1)2(x+1)x2−2x+1+2x(x−1)2(x+1)1x+1+1(x−1)⋅2x(x−1)(x+1)1x+1+1x−1(1x−1+1x+1)1x+1+1(x−1)2+1(x−1)(x+1)1x+1+1(x−1)2+12(x−1)−12(x+1)12(x+1)+1(x−1)2+12(x−1)

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