Resolve the following into partial fractions : 1/(x-1)²(x+4)
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Answered by
0
Answer:
1/x³+2x²-7x+4
Step-by-step explanation:
1/x²+1-2x(x+4)
1/x³+4x²+x+4-2x²-8x
1/x³+2x²-7x+4
Answered by
2
Answer:
======x2+1(x−1)2(x+1)x2−2x+1+2x(x−1)2(x+1)1x+1+1(x−1)⋅2x(x−1)(x+1)1x+1+1x−1(1x−1+1x+1)1x+1+1(x−1)2+1(x−1)(x+1)1x+1+1(x−1)2+12(x−1)−12(x+1)12(x+1)+1(x−1)2+12(x−1)
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