Question

resolve the partial fraction (x-1)(x-2)(x-3)
$\div$
(x-4)(x-5)(x-6)​

Answer 1

Step-by-step explanation:

$\frac{(x - 1)(x - 2)(x - 3)}{(x - 4)(x - 5)(x - 6)}$

$\frac{ ({x}^{2} - 2x - x + 2)(x - 3)}{ ( {x}^{2} - 5x - 4x + 20)(x - 6) }$

$\frac{( {x}^{2} - 3x + 2)(x - 3) }{( {x}^{2} - 9x + 20)(x - 6) }$

$\frac{ {x}^{3} - 3 {x}^{2} - 3 {x}^{2} + 9x + 2x - 6 }{ {x}^{3} - 6 {x}^{2} - 9 {x}^{2} + 54x + 20x - 120 }$

$\frac{{x}^{3} - 6 {x}^{2} + 11x - 6}{ {x}^{3} - 15 {x}^{2} + 74x - 120 }$