resolve x²+1/(x²+2)(x²+3)
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Let(2x+3)(x−3)(x+1)+A(x−3)+B(x+1).then
2x+3(x−3)(x+1)=A(x+1)+B(x−3)(x−3)(x+1)
or(2x+3)≡A(x+1)+B(x−3).
Putting (x−3)=0orx=3in (i) , we get A=(9/4).
Putting (x+1)=0orx=−1in (i),we get B=(−1/4).
∴(2x+3)(x−3(x+1))=94(x−3)−14(x+1)
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