Question

Resolve x²+2÷(x+1)(x-2)
into partial fractions.​

Answer 1

Answer:

$\sf = > \frac{ {x}^{2} + 2}{(x + 1)(x - 2)}$

$\sf = > \frac{ {x}^{2} - 2 }{ {x}^{2} - 3 }$

Step-by-step explanation:

$\sf \red{let \: us \: solve \: this \: using \: the \: }$

$\sf \red{identity \: }(x + a)(x + b)$

$\sf{ \underline{ \underline{where \ \: : }}}$

$\bf \: x \: = \: x$

$\bf \: a \: = \: 1$

$\bf \: b \: = \: - 2$

$\sf(x + 1)(x - 2) \ \: :$

$\sf = > {x}^{2} + (1 + - 2) + 1 \times - 2$

$\sf = > {x}^{2} + x( - 1) + ( - 2)$

$\sf = > {x}^{2} - 1 - 2$

$\bf \red{= > {x}^{2} - 3}$