Physics, asked by bhagyashripatil204, 7 months ago

Resolving power of a telescope whose objective
lens has diameter 1.22m for a wavelength 4000 Å.​

Answers

Answered by Ekaro
6

12th/Physics

Wave optics

Answer :

Diameter of objective lens = 1.22m

Wavelength of light = 4000Å

We have to find resolving power of telescope .

★ Resolving power of telescope is given by

  • RP = D/1.22λ

D denotes diameter of lens

λ denotes wavelength of light

➙ RP = D/1.22λ

➙ RP = (1.22×10⁷)/(1.22×4)

➙ RP = 0.25 × 10⁷

RP = 2.5 × 10

★ Resolving power of microscope is given by

  • RP = 2μsinθ/λ

Cheers!

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