Resolving power of a telescope whose objective
lens has diameter 1.22m for a wavelength 4000 Å.
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12th/Physics
Wave optics
Answer :
Diameter of objective lens = 1.22m
Wavelength of light = 4000Å
We have to find resolving power of telescope
★ Resolving power of telescope is given by
- RP = D/1.22λ
D denotes diameter of lens
λ denotes wavelength of light
➙ RP = D/1.22λ
➙ RP = (1.22×10⁷)/(1.22×4)
➙ RP = 0.25 × 10⁷
➙ RP = 2.5 × 10⁶
★ Resolving power of microscope is given by
- RP = 2μsinθ/λ
Cheers!
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