Question

respect to a
Diffraciade with
;)( x3-2x-1)5​

Answer 1

AnswEr :

Let y = (x³ - 2x - 1)^5

We have to find the derivative of y

Now,

$\sf y' = \dfrac{d(x {}^{3} - 2x - 1) {}^{5} }{dx}$

Using Chain Rule of Differentiation,

$\leadsto \: \sf y' = 5(x {}^{3} - 2x - 1) {}^{4} \times \dfrac{d(x {}^{3} - 2x - 1)}{dx} \\ \\ \leadsto \sf \: y' = 5( {x}^{3} - 2x - 1) {}^{4} (3 {x}^{2} - 2) \\ \\ \leadsto \: \boxed{ \boxed{\sf y' = 5( 3{x}^{2} - 2) {(x {}^{3} - 2x - 1) }^{4} }}$

Answer 2

Answer:

5(3x²-2) (x³-2x-1)⁴

Step-by-step explanation:

(In Attachment)

Answer by S Salik

Answer by S Salik[ Follow to hit your doubts out of the boundary]