Respiration is an exothermic process. explain?
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Answer:Respiration is considered as an exothermic reaction because in respiration oxidation of glucose takes place which produces large amount of heat energy. This is shown in following chemical equation.
Answered by
3
During respiration, glucose molecules are converted to other molecules in a series of steps. They finally end up as carbon dioxide and water. The reaction is exothermic because the C=O and O-H bonds in the products are so much more stable than the bonds in the reactants.
During respiration, glucose molecules are converted to other molecules in a series of steps.
They finally end up as carbon dioxide and water.
The overall reaction is
C
6
H
12
O
6
+
6O
2
→
6CO
2
+
6H
2
O
+
2805 kJ
The reaction is exothermic because the
C=O
and
O-H
bonds in the products are so much more stable than the bonds in the reactants.
Bond energy is the average energy needed to break a bond.
Some bond energies are:
C-C
= 347 kJ/mol
C-H
= 413 kJ/mol;
C-O
= 358 kJ/mol;
O-H
= 467 kJ/mol;
O=O
= 495 kJ/mol;
C=O
= 799 kJ/mol
We can view the process as breaking all the bonds in the reactants to separate the atoms and then re-combining the atoms to form the bonds in the products.
A glucose molecule has the formula
It contains 5
C-C
, 7
C-H
; 7
C-O
, and 5
O-H
bonds.
The 6
O
2
molecules contain 6
O=O
bonds.
The products contain 12
C=O
and 12
O-H
bonds.
The overall process is
5C-C
l
+
7C-H
+
7C-O
+
5O-H
+
6O=O
→
12C=O
+
7
12
O-H
or
5C-C
l
+
7C-H
+
7C-O
+
6O=O
break these bonds
→
12C=O
l
+
7O-H
form these bonds
The energy differences in kilojoules per mole are
l
5C-C
+
l
7C-H
+
7C-O
l
+
l
6O=O
l
→
12C=O
+
l
5O-H
5×347
+
7×413
+
7×358
+
l
6×495
l
→
12×799
+
7×467
l
1735
l
+
l
2891
l
+
l
2506
l
+
l
l
2970
m
→
m
9588
l
l
+
l
3269
m
m
m
m
m
m
m
10 102
m
m
m
m
m
m
m
l
→
m
m
m
12 857
Δ
H
≈
(10 102 - 12 857) kJ/mol
=
-2755 kJ/mol
Almost 75 % of the energy released comes from formation of the stable
C=O
bonds in
CO
2
.
During respiration, glucose molecules are converted to other molecules in a series of steps.
They finally end up as carbon dioxide and water.
The overall reaction is
C
6
H
12
O
6
+
6O
2
→
6CO
2
+
6H
2
O
+
2805 kJ
The reaction is exothermic because the
C=O
and
O-H
bonds in the products are so much more stable than the bonds in the reactants.
Bond energy is the average energy needed to break a bond.
Some bond energies are:
C-C
= 347 kJ/mol
C-H
= 413 kJ/mol;
C-O
= 358 kJ/mol;
O-H
= 467 kJ/mol;
O=O
= 495 kJ/mol;
C=O
= 799 kJ/mol
We can view the process as breaking all the bonds in the reactants to separate the atoms and then re-combining the atoms to form the bonds in the products.
A glucose molecule has the formula
It contains 5
C-C
, 7
C-H
; 7
C-O
, and 5
O-H
bonds.
The 6
O
2
molecules contain 6
O=O
bonds.
The products contain 12
C=O
and 12
O-H
bonds.
The overall process is
5C-C
l
+
7C-H
+
7C-O
+
5O-H
+
6O=O
→
12C=O
+
7
12
O-H
or
5C-C
l
+
7C-H
+
7C-O
+
6O=O
break these bonds
→
12C=O
l
+
7O-H
form these bonds
The energy differences in kilojoules per mole are
l
5C-C
+
l
7C-H
+
7C-O
l
+
l
6O=O
l
→
12C=O
+
l
5O-H
5×347
+
7×413
+
7×358
+
l
6×495
l
→
12×799
+
7×467
l
1735
l
+
l
2891
l
+
l
2506
l
+
l
l
2970
m
→
m
9588
l
l
+
l
3269
m
m
m
m
m
m
m
10 102
m
m
m
m
m
m
m
l
→
m
m
m
12 857
Δ
H
≈
(10 102 - 12 857) kJ/mol
=
-2755 kJ/mol
Almost 75 % of the energy released comes from formation of the stable
C=O
bonds in
CO
2
.
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