Question

Restionalise the denominator of 1/root 9 _root 8

Answer 1

Answer:

$\sqrt{9} + \sqrt{8}$

Step-by-step explanation:

$\frac{1}{ \sqrt{9} - \sqrt{8} } \\ \\ rationalising \: denominator \: of \\ \: \sqrt{9} - \sqrt{8} \: is \: \sqrt{9} + \sqrt{8} \\ \\ = \frac{1}{ \sqrt{9} - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} } \\ \\ = \frac{ \sqrt{9} + \sqrt{8} }{9 - 8} \\ \\ = \sqrt{9} + \sqrt{8}$

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