Question

Restore into factors
(x+1)(x+ 3) (x-4)(x-6) +24
(a)​

Answer 1

Answer:

(x+1)= 1,x

(x+ 3) = x,3

(x-4) =x,-4

(x-6) =x,-6

+24=24

(a)=1,a

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Answer 2

Answer:

The answer is $(x^2-3x-6)(x^2-3x-16)$

Step-by-step explanation:

Given expression

         $(x+1)(x+3)(x-4)(x-6)+24$

      $=[(x+1)(x-4)][(x+3)(x-6)]+24$

      $=(x^2-3x-4)(x^2-3x-18)+24$

      $=(y-4)(y-18)+24$, let $x^2-3x=y$

      $=y^2-22y+72+24\\=y^2-22y+96\\=(y-6)(y-16)$

      $=(x^2-3x-6)(x^2-3x-16)$, since $y=x^2-3x$