resultant of three vectors of magnitude 10 each be 10 if angle be
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Perfect questions for guys interested in maths..
2. The value of x + x(xx) when x = 2 is:
(a) 10, (b) 16, (c) 18, (d) 36, (e) 64
Solution:
x + x(xx)
Put the value of x = 2 in the above expression we get,
2 + 2(22)
= 2 + 2(2 × 2)
= 2 + 2(4)
= 2 + 8
= 10
Answer: (a)
Explanation:
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Angle between the vectors
θ= 60°-30° =30°.
Hence magnitude of the resultant
= √(A²+B²+2ABcosθ)
= √(10²+10²+2.10.10.cos30°)
=√(200+200.√3/2)
=10√(2+√3)
= 19.32 units
Since the vectors have equal magnitudes so the resultant bisects the angle θ between them.
The angle between resultant and vector A =30°/2 =15°.
So angle between resultant and X-axis =15°+30° =45°
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