Question

Resultant of two forces 30N and 40N acting at angle of 90degree with each other will be?

Answer 1

Answer:

One of the forces is 14N and makes an angle of 45 degrees with the resultant. ... Two forces while acting on a particle in the opposite direction have the resultant of 10N. If they act at right angles to each other, the resultant is found to be 50N.

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Answer 2

Answer:

Resultant of two forces 30N and 40N acting at angle of 90degree with each other will be $50 N$

Explanation:

Of course, with a triangle with a 90° angle, a right triangle, you can simply use Pythagoras theorem  $(a^2+b^2=c^2)$  then SOH-CAH-TOA to solve for the angle  $(\theta=Cos-1(\frac{adjacent}{hypotenuse} )) .$

But what if it isn't a right triangle? The cosine rule works for all triangles, even if they don't have a 90° angle.

$a^2=b^2+c^2−2(b)(c)Cos(A)$

Where a is the missing side, and A is the angle opposite to side a.

With this rule, we can find a missing angle or a missing side to any type of triangle, assuming you have the needed variables.

Let's plug your example in:

Let b=40 c=30 and A=90°

$a^2=40^2+30^2-2(40)(30)Cos(90)$

Cos(90)=0 which is why Pythagoras theorem works at 90°, but I'll continue as if it did matter.

$a^2=2500-2(40)(30)Cos(90)$

$a^2=2500-2400*0$

$a=\sqrt{2500}$

$a=50N$

Reference Link

• https://brainly.in/question/9282
• https://brainly.in/question/31028726