Question

Resultant of two forces P and Q is
√3 Q. The resultant
is inclined at 30° with P. Show that, either P = Q or
P = 2Q.​

Answer 1

$R=\sqrt{P^2+Q^2+2PQ COS @}$

SO by putting all the given values

3Q^2=P^2+Q^2+2PQ $\sqrt{3} /2$

BY CONSIDERING THIS AS A QUADRATIC EQUATION WE WILL GET THE VALUES IN TURN

P=2Q

Answer 2

In this way we can prove it simply by applying cosine law..