Resultant of two froce 3N nad 4N acting ar apoit is 5N show that the two froce are 2 perpendicular to each other
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Given:
- Two forces, A = 3N and B = 4N
- Resultant of these forces, R = 5N
To prove:
- Two forces are perpendicular to each other.
Knowledge required:
- Formula to calculate magnitude of resultant 'R' of two forces 'A' and 'B' when they are at an angle 'p' to each other.
R² = A² + B² + 2 AB cos p
Proof:
Let, the angle between A and B be 'p', then the resultant R will be,
➡ R² = A² + B² + 2 AB cos p
[ putting values ]
➡ (5)² = (3)² + (4)² + 2 (3) (4) cos p
➡ 25 = 9 + 16 + 24 cos p
➡ 25 = 25 + 24 cos p
➡ 25 - 25 = 24 cos p
➡ 0 = 24 cos p
➡ cos p = 0
[ since, cos 90° = 0 ]
➡ cos p = cos 90°
➡ p = 90°
Hence, Proved that
- Forces A = 3N and B = 4N are Perpendicular to each other.
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