Physics, asked by mazharmaham711, 19 days ago

resultant of two perpendicular vectors of equal magnitude?

Answers

Answered by fayzaanrashidlone
3

Answer:

 \sqrt{2 \: }  \: a

Explanation:

because resultant of two perpendicular (<=90) vector =

 \sqrt{a  {}^{2}  + b {}^{2} } a=b because magnitude is equal

now resultant =

 \sqrt{a {}^{2}  + a {}^{2} }  =  \sqrt{2a { }^{2} }  =  \sqrt{2 \:  } a

Answered by advmanojsingh505
0

Solution:

Solution given as per question since the resaultant of two given vectors R =

___________________

✓ A2 + B2 + 2ABcos0

_______________

x = ✓ x2 + x2 + 2x2cos0

x2 = 2x2 + 2x2cos0

2x2cos0 = - x2

cos0= - X2

cos0 = - 1 ÷ 2

cos0 = - cos120°

Comparing both sides , 0 = 120°

Hence , the angle between two given vectors is 120°

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