Math, asked by kpriyakumarr, 11 months ago

Resultant price of mixture of golden rice is Rs. 480 per kg. This mixture is made from two varieties of golden rice which are having price of Rs. 420 per kg and Rs. 520 per kg. What should be ratio of quantities of both types of golden rice? ​

Answers

Answered by Anonymous
5

✓✓✓✓✓✓✓✓✓✓>>>>>✌️

@NSWER

✓ price of golden rice(mixture)=480 Rs/kg

✓ the price of golden rice{A)=420Rs/kg

✓and the price of golden rice (B)=520Rs/kg

✓✓now let X kg of A is mixed with y kg of B.....

✓✓now according to the problem

✓X×420+y×520=(X+y)480

✓520y-480y=480x-420x

✓40y=60x

✓x/y=40/60

x/y=2/3

therefore two types of rice of price rate 420 rs/kg and 520 rs /kg are mixed with a ratio of 2:3 in per kg......

::::::;[]

Answered by halamadrid
0

The ratio of quantities of both types of golden rice is 2/3.

Given:

The resultant price of a mixture of golden rice is Rs. 480 per kg.

The mixture is made from two varieties of golden rice that are having prices of Rs. 420 per kg and Rs. 520 per kg.

To Find:

The ratio of quantities of both types of golden rice.

Solution:

We are given that the resultant price of the mixture of golden rice is Rs. 480 per kg.

It is given that this mixture is made from two varieties of golden rice.

Let 'x' be the amount of the first variety of rice used and let 'y' be the amount of the second variety of rice used.

∴ Price of x = Rs. 420 per kg and price of y = Rs. 520 per kg.

The total price of the golden mixture can be found by multiplying the price of each variety of rice by their respective amount.

∴ The total price of the golden mixture = 420x + 520y .....................(I)

The total price can be found by multiplying the total amount of rice by the total price per kg.

The total amount of rice = x+y .....................(II)

⇒ Total price of rice = 480(x + y)

From equations (I) and (II),

420x + 520y = 480(x + y)

⇒ 520y - 480y = 480x-420x

⇒ 40y = 60x

⇒ x/y = 40/60 = 2/3.

∴ The ratio of quantities of both types of golden rice is 2/3.

#SPJ3

Similar questions