Question

Retailer retailer sold three cameras rupees 28500 and had a loss of 5% find the cost price of each camera

Answer 1

Answer :-

• The cost price of each camera is Rs 10000.

To find :-

• The cost price of each camera.

Step-by-step explanation :-

• Here, it is given that the selling price of three cameras is Rs 28500 and the loss percentage is 5%. We have to find the cost price of each camera!

Let :-

• The cost price of the three cameras be Rs "x".

Then :-

• Loss = 5% of x

Therefore, the loss is :-

$\sf{ \longrightarrow \cancel{\dfrac{5}{100}} \times x}$

$\sf{\longrightarrow \dfrac{1}{20} \times x}$

$\sf{ \longrightarrow \: Rs \: \dfrac{x}{20}}$

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Now, we know that :-

$\underline{\boxed{\sf{SP = CP - Loss}}}$

Where,

• SP = Selling price.
• CP = Cost price.

Here,

• Cost price = Rs "x".
• Selling price = Rs "x/20".

Therefore,

$\longrightarrow\sf{SP = x - \dfrac{x}{20}}$

$\longrightarrow \sf SP = \dfrac{x \times 20 - x \times 1}{20}$

$\longrightarrow\sf SP = \dfrac{20x - x}{20}$

$\longrightarrow\sf{SP = Rs \: \dfrac{19x}{20}}$

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Now, given that :-

• The selling price is Rs 28500.

Therefore,

$\sf{\longrightarrow \: \dfrac{19x}{20} = 28500}$

$\sf{\longrightarrow \: 19x = 28500 \times 20}$

$\sf{\longrightarrow \: 19x = 570000}$

$\sf{\longrightarrow \: x = Rs \: 30000}$

Hence :-

• The cost price of the three cameras is Rs 30000.

And :-

• The cost price of each camera = 30000/3 = Rs 10000.

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