Question

retardation?
d) Maruti Suzuki accelerates uniformly from rest to a speed of 5.20 m/s
over a distance of 85.5 m. Determine the acceleration of the bike.
​

Answer 1

Answer:

Given, initial velocity, u=0m/s and final velocity v=7.10m/s

Distance traveled S=35.4m

If a be the acceleration.

Using formula v

2

−u

2

=2aS

(7.10)

2

−0

2

=2a(35.4)

⟹ a=0.712m/s

2

Step-by-step explanation:

Hope it helps you ☺️