Retardation of a car travelling at 54km and the car is brought to rest over a distance of 60m and the frictional resistance is 200N and the mass of the car is 850kg
proton1:
what to calculate
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Answered by
1
hii
here is your answer
2as=v^-u^
2×a×60= 0-15^
120a =225
a=225/120
a=-1.8
hope it helps
here is your answer
2as=v^-u^
2×a×60= 0-15^
120a =225
a=225/120
a=-1.8
hope it helps
it is wrong
why
question does not have proper values of particulars.
Answered by
0
this question have errors and also not give what we have to found
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