return of 1, 2, 3 ohm are connected in the form of a triangle if a 1.5 volt cell of negligible internal resistance is connected across 3 ohm resistor the current flowing through this resistance will be
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Explanation:
Fig1
1ohm and 2ohm resistors are connected
in series. Therefore effective resistance
= sum= 3ohm
Now the two 3ohm resistors are connected in parallel(fig.2), so
1/R=1/3+1/3=2/3
R=3/2ohm
we know current I=V/R
=1.5×2/3
=1A
Hope it helps
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