Chemistry, asked by pavithrabaratam745, 9 months ago

reversible expansion of 2 mole of an ideal gas
from a volume of 10dm3 to a volume of 100dm3
at 27°C is​

Answers

Answered by ARKRANGER
1

Answer: the answer is = 38.3 J mol-1K-1

Entropy for isothermal process -

\Delta S= nR\ln \frac{V_{f}}{V_{i}}

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\Delta S= nR\ln \frac{P_{i}}{P_{f}}

 

- wherein

T_{f}=T_{i}

\Delta T=0

 

\Delta S= nRln \frac{V1}{V2}=2.303 nR \log \frac{V_{1}}{V_{2}}

=2.303 \times 2 \times 8.314 \times log \frac{100}{10}

= 38.3 J mol-1K-1

Explanation:

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