Question

Review An object moving in a straight line covers half of the distance with speed 5 m/s. The other half of the distance is covered in two equal time intervals with speed of 4 m/s and 6 m/s respectively. The average speed of object during the motion is​

Answer 1

Step-by-step explanation:

This is the answer

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Answer 2

Speed and Distance

A path  S is divided into three paths.

The first path is of half of the distance of whole path and covered with a speed of $5m/s$.

The other half is divided into further two parts and covered with the speed of $4 m/s \ and \ 6m/s$.

Let the time taken in covering first part be t₁.

The time taken in covering second and part is equal and be t₂ and t₃ respectively.

According to question,

$t_1=\frac{(\frac{s}{2}) }{5} =\frac{S}{10}$

and,

$\frac{S}{2}=4\times t_2+6\times t_3\\\\\implies \frac{S}{2}=10t_2$(since t₂= t₃)

$\implies {S} =20t_2$

Total time taken will be, $t_1+t_2+t_3$ $=\frac{S}{10}+ \frac{S}{20} +\frac{S}{20}= \frac{S}{5}$

Average speed of the object during the motion is

$\frac{S}{t}=\frac{S}{\frac{S}{5} }=5 \ m/s$

Hence, average speed is 5 m/s.