Question

Revisit
Question #1
In a class, marks scored by one of the students are written as 92 instead of 56. Due to this, the
average marks of the class is increased to 72.50 marks from 71.75 marks. If the marks of two more
students are included as 52 and 54 marks, then the average marks of the students will be

A 70.5
B 71
C. 71.5
D. 72​

Answer 1

Answer:

71 is the answer of this question

Answer 2

Average

Given:

92 was written in place of 56, average marks increases from 71.75 to 72.50 marks.

To find:

The average marks of students will be , when 2 marks 52, 54 are added.

Step by step explanation:

1. First find the difference in average.
2. Calculate the difference in marks written in place of marks correct marks.
3. Divide the difference in step 2 with difference in step 1.
4. Multiply the result from step 3 with the average calculated initially.
5. Add the new marks and find the new average.

Calculation:

$(92-56)=36$,difference in marks.

$\frac{36}{(72.50-71.75)} \\\\=\frac{36}{0.75}$,Division of  the difference in marks with difference in average.

$=48$

Multiply the average calculate initially with the difference we get,

$48$ × $71.75=3444$

Add the new numbers,

$3444+52+54=3550$

Divide this marks with $(48+2)=50$ to find the average

$\frac{3550}{50} =71$

Hence the required average marks will be 71.