revolver of mass 500 gram fire A bullet of mass 10 gram with a speed of 100 M per second find momentum of the bullet initial momentum of the revolver and the bullet and equal velocity of revolver
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Find:
(a) Initial momentum of ‘ gun + bullet ‘ .
As initially both the gun and the bullet are at rest so the velocity of both bullet and gun is 0.
Therefore, the initial momentum of gun and bullet, pi = Mvi+mvi’ = 0
(b) Momentum gained by the bullet after firing.
Momentum gained by the bullet after firing, p = mv = 0.01×100 = 1 kg m s-1
(c) Recoil velocity of the gun
Let the recoil velocity of the gun be V.
From conservation of momentum,
Final momentum of the system = initial momentum of the system
MV +mv = 0
⇒0.5×V = -1
⇒V = – 1/0.5 = -2 m/s
(a) Initial momentum of ‘ gun + bullet ‘ .
As initially both the gun and the bullet are at rest so the velocity of both bullet and gun is 0.
Therefore, the initial momentum of gun and bullet, pi = Mvi+mvi’ = 0
(b) Momentum gained by the bullet after firing.
Momentum gained by the bullet after firing, p = mv = 0.01×100 = 1 kg m s-1
(c) Recoil velocity of the gun
Let the recoil velocity of the gun be V.
From conservation of momentum,
Final momentum of the system = initial momentum of the system
MV +mv = 0
⇒0.5×V = -1
⇒V = – 1/0.5 = -2 m/s
manish8362:
thanks for your help
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