Question

Rewrite in factored form:
6p^2 + 19p - 7

Answer 1

$hi \: ...$

$here \: is \: your \: answer \: ...$

$6 {p}^{2} + 19 p - 7 = 0$

This eqn is in the form

$a {x}^{2} + bx + c = 0$

multiplying a & c

(6)(-7) = -42

21 × (-2) = -42

Also ,

21 - 2 = +19

Therefore ,

Simplifying the equation

$6 {p}^{2} + 21p - 2p - 7 = 0$

$3p(2p + 7) - 1(2p + 7) = 0$

$(2p + 7)(3p - 1) = 0$

Thus , the answer is option c)

$(2p + 7)(3p - 1)$

are the factors ...

$hope \: this \: helps....$

Answer 2

Answer:

Answer is 2p+7 3p-4

Step-by-step explanation:

Thanks