Rewrite 'y' removing the modulus & hence answer the following
questions:
y = |x – 11 – 12x + 31 – 2
Answer the following questions:
Q.2) 2x + 3 is positive for what values of x ?
Q.3) For -1.5 < x < 1, y takes the form -
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Answer:
Heya mate your answer
Step-by-step explanation:
Q.2)Complete the square:
x² - 2x - 3 > 0
<=> ( x - 1 )² - 4 > 0
<=> ( x - 1 )² > 4
<=> | x - 1 | > 2
<=> x -1 > 2 or x -1 < -2
<=> x > 3 or x < -1
Q.3) {\displaystyle 1/(p-B)}{\displaystyle 1/(p-B)}, for {\displaystyle B=N(\mu ,\sigma )}B=N(\mu ,\sigma )
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