Question

rezaul claps 10 times in a second in front of a clip. if he is standing at a distance of 1450 cm from the Cliff, then the clap sound and its echo coincide. find the velocity of the sound.​

Answer 1

Solution-

Time interval between two claps = 0.1 second.

∴ Time required for an echo = 0.1 second.

Now, v = 2d/t

= 2 × 14.5/0.1

= 290 m/s

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Echo: An echo is a repitition of sound caused by the reflection of a sound wave at a distant building, hill, trees or other obstacles. The distance d of obstacle that causes and echo is given by 2d= v×t.

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Answer 2

Answer:

Time interval between two claps = 0.1

Second

Time required for an echo = 0.1 second

Now ,v =2d/t

= 2×14.5 /0.1

= 290 m/s

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