Question

Rhea's motheris four times as old as she is now In 20 years the mother will be twice as old as her daughter. find their present age ?​

Answer 1

Answer:

their present ages will be >>> rhea = x = 10years and mother = 4x = 4(10) = 40years

Step-by-step explanation:

let the age of rhea be x then, mother will be 4x

after 20 years they will be >>> rhea = (x+20)years

                                                     mother = (4x+20)years

so ATP,

4x + 20 = 2(x+20)

4x+20 = 2x+40

4x-2x = 40-20

2x = 20

x = 20/2 = 10

so their present ages will be >>> rhea = x = 10years and mother = 4x = 4(10) = 40years

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