Question

Rhombus BEND
BN = 5.6 CM
DE = 6.5 CM

Answer 1

Step-by-step explanation:

Construction:-

(1) Draw a line segment BN of 5.6 cm and also draw its perpendicular bisector. Let it intersect the line segment BN at point O.

(2) Taking O as centre, draw arcs of 3.25 cm radius to intersect the

perpendicular bisector at point D and E.

(3) Join points D and E to points B and N.

BEND is the required quadrilateral.