Question

rhombus measured 16cm & 30cm.
8) The diagonals of
Find its perimeter
​

Answer 1

Answer:

68cm

Step-by-step explanation:

Let ABCD be the given rhombus.

We know that the Diagonals of a rhombus are perpendicular bisector of each other. Let the point of intersection of diagonals AC and BD be M.

Given AC = 30 cm

and BD = 16 cm  

Now, AM = AC/2

= 30/2 =

15 cm

and

DM = BD/2

= 16/2

= 8 cm

Now, in right triangle AMD, by pythagoras theorem,  

AD2 = AM2 + MD2

⇒AD2 = 152 + 82

⇒AD2 = 225 + 64 = 289

⇒ AD = √289 = 17 cm

Again, all the sides of a rhombus are equal.

∴ , AB = BC = CD = AD = 17 cm

Now the perimeter of a rhombus

= sum of all sides = AB+BC+CD+AD=68cm