rhombus wala questions ka answer
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AR(ABC)=AR(ACD)=2AR(ABCD)
AR(ABC)=48cm²(by herons formula)
AR(ABCD)=96cm²
d₁xd₂/2=96
6xd₂=96
d₂=16cm
AR(ABC)=48cm²(by herons formula)
AR(ABCD)=96cm²
d₁xd₂/2=96
6xd₂=96
d₂=16cm
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in a rhombus diagonals bisect each other perpendicularly.
draw a rough figure ABCD rhombus.diagonal AC = d1, diagonal BD = d2
intersect at O
therefore triangle AOB is rightangle triangle
given one side = hypotenuse =AB = 10cm
AC =d1 = 12 cm
OA = d1/2 =12/2 = 6cm
OB =√AB²-OA²
=√10²-6²
=√100-36
=√64
=8
OB=8CM
d2 =2*8=16 cm
draw a rough figure ABCD rhombus.diagonal AC = d1, diagonal BD = d2
intersect at O
therefore triangle AOB is rightangle triangle
given one side = hypotenuse =AB = 10cm
AC =d1 = 12 cm
OA = d1/2 =12/2 = 6cm
OB =√AB²-OA²
=√10²-6²
=√100-36
=√64
=8
OB=8CM
d2 =2*8=16 cm
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