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If resistors of R1, R2 and R3 ohms are connected in parallel as shown in the
figure to make an R-ohm resistor, then value of R can be found from the
equation If R1= 45, R2 = 30, and R3 = 90 ohms, then find
the rate of change of resistance R1 with respect to resistance R.
Answers
Answer:
the war photograph will help you to know the answer
Answer:
The value of R = 2/3(30 + 45 + 90) = 160 ohms
Step-by-step explanation:
From the above question,
They have given :
QUESTION :
If resistors of R1, Rz, and R3 ohms are connected in parallel to make an R-ohm resistor; the value of R can be found from the equation = K+% + R R3 DR Find the value of when R1 = 30, Rz = 45, Rx = 90 and TR2 R =1 5 ohms Show your answer in the form a/b; e.g-,3/4,3/1,-1/2.
Find the value of k:
k = 2/3(1/R1 + 1/R2 + 1/R3)
= 2/3(1/30 + 1/45 + 1/90)
= 2/3(1/2 + 1/3 + 1/2)
= 2/3(-1/2 + 1/3 - 1/2)
= 2/3(-1/2 - 1/2)
= -1/3
Substitute the values of k and the values of R1, R2 and R3 in the equation:
R = k(R1 + R2 + R3)
= -1/3(30 + 45 + 90)
= -1/3(165)
= -55
Since the value of R cannot be negative, the correct equation is:
R = 2/3(R1 + R2 + R3)
Substitute the values of R1, R2 and R3 in the equation:
R = 2/3(30 + 45 + 90)
= 2/3(165)
= 110
Therefore, the value of R is 110 ohms.
The value of R = 2/3(30 + 45 + 90) = 160 ohms
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